Solving for x in a quadtratic equation

[Gr8fu13]

The problem is solve for x.
x^2+12x+4=0

Here is what I did:
(-12±?(?12?^2-4(1)(4)))/(2(1))
(-12±?(144-16))/2
(-12±?128)/2
(-12±?(36*5))/2
(-12±?36*?5)/2
(-12±6?5)/2

I have my answer as:
-6+3?5, -6-3?5
Is this accurate? If not, please show me what I did wrong…

 

[Deleted member 4993]

The problem is solve for x.
x^2+12x+4=0

Here is what I did:
(-12±?(?12?^2-4(1)(4)))/(2(1))
(-12±?(144-16))/2
(-12±?128)/2
(-12±?(36*5))/2 <<<< How did you get that 36*5 = 180 - however - 128 = 64*2
(-12±?36*?5)/2
(-12±6?5)/2

I have my answer as:
-6+3?5, -6-3?5
Is this accurate? <<<< No - see above

If not, please show me what I did wrong…

 

[Gr8fu13]

Woops, I mixed two of my problems Let me see if I can correct:

Here is what I did:
(-12±?(?12?^2-4(1)(4)))/(2(1))
(-12±?(144-16))/2
(-12±?128)/2
(-12±?(64*2))/2
(-12±?64*?2)/2
(-12±8?2)/2

I have my answer as:
-6+4?2, -6-4?2
Is this accurate?

 

[Deleted member 4993]

Woops, I mixed two of my problems Let me see if I can correct:

Here is what I did:
(-12±?(?12?^2-4(1)(4)))/(2(1))
(-12±?(144-16))/2
(-12±?128)/2
(-12±?(64*2))/2
(-12±?64*?2)/2
(-12±8?2)/2

I have my answer as:
-6+4?2, -6-4?2
Is this accurate?

Looks good to me...