Solving for x, given y = (x + 3) / (x - 2)

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BigNate

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Oct 2, 2016
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Hello,

How would I go about solving for x in the following equation?

y=(x+3)/(x-2)

Can someone please point me in the right direction?

Thank you!
 
BigNate said:
Hello,

How would I go about solving for x in the following equation?

y=(x+3)/(x-2)

Can someone please point me in the right direction?

Thank you!
Click to expand...
One of the ways:

y=(x+3)/(x-2)

y = 1 + 5/(x-2)

continue.....
 
BigNate said:
I appreciate your response, but I am still confused. How did the (x+3) turn into 1+5?

Thanks!
Click to expand...
Looks like you have forgotten basic algebra and "hierarchy of operation"

(x+3)/(x-2) = (x - 2 + 5)/(x-2) = (x-2)/(x-2) + 5/(x-2) = 1 + 5/(x-2)

Middle school stuff...
 
BigNate said:
Hello,

How would I go about solving for x in the following equation?

y=(x+3)/(x-2)

Can someone please point me in the right direction?

Thank you!
Click to expand...

y(x-2) = x+3 .....multiply both sides by (x-2)

yx - 2y = x+3 ..... expand bracket

yx -x = 2y+3 .... get all the terms with x on one side of the equation

Now factorise the LHS and see what happens.
 
BigNate said:
How would I go about solving for x in the following equation?

y=(x+3)/(x-2)

Can someone please point me in the right direction?
Click to expand...
There's a trick to this. Try here to find a description and see a worked example. ;)
 
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