solving for x algebra questions

[mathusername]

Can anyone please give me a step by step guide on solving these particular questions. I seem to be confused on doing the mathematical work with the square roots.
sqrt(5x+ 1)= 6
cubert(3x+ 10)= 4
sqrt(16+ x)= 8- sqr(x)

 

[Deleted member 4993]

Can anyone please give me a step by step guide on solving these particular questions. I seem to be confused on doing the mathematical work with the square roots.
sqrt(5x+ 1)= 6
cubert(3x+ 10)= 4
sqrt(16+ x)= 8- sqr(x)

Hint for #1:

Square both sides to get:

(5x + 1) = 6²

similarly for #2

cube both sides.

(3x + 10) = 4³

and so on.....

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[mathusername]

Thank you for the re formating of the first two questions. It solved my problem on how to solve them. Could you please tell me what to do on the third question where you have two square roots.

 

[HallsofIvy]

Same thing- to get rid of a square root, you need to square. So start by squaring both sides of the equation. The result will still have a square root in it so isolate that square root and square again.