Solving for all real values of X.

[da5id]

Hi, I am stuck on this problem: x[sup:2yf4e2sh]2[/sup:2yf4e2sh]-9x+9=0

Can someone help me walk me through this problem? Thanks in advance!

 

[Deleted member 4993]

Hi, I am stuck on this problem: x[sup:78zfmi1c]2[/sup:78zfmi1c]-9x+9=0

Can someone help me walk me through this problem? Thanks in advance!

To find roots of quadratic equation - please look at example problems at:

http://www.purplemath.com/modules/quadform.htm

.

 

[fasteddie65]

x^2 - 9x + 9 = 0 is not factorable, so we must use Quadratic Formula or complete the square. Since b is not even, completing the square is not that simple, involving fractions and all. So use Quadratic Formula.

x = [-b ± ?(b^2 - 4ac)]/(2a) = {-(-9) ± ?[(-9)^2 - 4(1)(9)]}/(2•1) = [9 ± ?(81 - 36)]/2 = [9 ± ?45]/2 = [9 ± 3?5]/2