solving equations for x: 10x = 8, 12 = e^5x, 2^4x = 2^2x-6

[leeborrett]

I'm relatively new to this type of equation and am only used to more simple equations where the values are more defined. Can anyone help with any of the following?

. . .1) 10x = 8

. . .2) 12 = e to the power 5x

. . .3) 2 to the power 4x = 2 to the power 2x-6

It would be very much appreciated if you could give me any guidence. Thank you!

 

[stapel]

I'm not sure what you mean by "more defined"...? I don't see any ambiguity in the posted equations.

1) Divide through by ten.

2) Assuming you mean "12 = e^5x", take the natural log of both sides, and then divide off the 5.

3) Assuming you mean "2^4x = 2^{2x - 6}", equate the powers (since you've got the same base) and solve the linear equation.

If the above doesn't make sense, please clarify what sort of equation you can solve, so we can try to find links to lessons that will fill in the gaps.

Thank you.

Eliz.