Solving equations by factoring

surge21

New member
Joined
Mar 22, 2010
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2
I am having such a difficult time with this problem and it seems so simple but I can't get it!

Here's what I got:
0 = 2y^2 - 4y + 2
(2y – 2)(y + 2) {y = 1, y = -2}

Here's the problem:
y^2/30 = y/15 + 1/2

I need a solution set and thus came up with 1 and -2 but i think it's wrong because it doesn't produce an answer of 0 with either one.
 
surge21 said:
Here's what I got:
0 = 2y^2 - 4y + 2
(2y – 2)(y + 2) {y = 1, y = -2}

Here's the problem:
y^2/30 = y/15 + 1/2
How in heck did you get what you got? :shock:

y^2/30 = y/15 + 1/2 ; multiply by 30:
y^2 = 2y + 15
y^2 - 2y - 15 = 0
Kapish?
 
I have the following roots
for
2y[sup:3nr2ntdd]2[/sup:3nr2ntdd]+4y+2=0
y1=-1
y2=-1

y[sub:3nr2ntdd]2[/sub:3nr2ntdd]-2y-15=0
y1=-3
y2=5
 
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