Hello
This is the last question in a section where all the other questions were exponential equations that could be solved by expressing them as quadratic equations. This is the only question that has logs in it. I'm guessing it's a 'disguised' quadratic too and would like to know how to express it as such.
The question is solve:
\(\displaystyle 1 + \log_{2} x = \dfrac{12}{\log_{2}x}\)
Thank you.
This is the last question in a section where all the other questions were exponential equations that could be solved by expressing them as quadratic equations. This is the only question that has logs in it. I'm guessing it's a 'disguised' quadratic too and would like to know how to express it as such.
The question is solve:
\(\displaystyle 1 + \log_{2} x = \dfrac{12}{\log_{2}x}\)
Thank you.
