solving differential equation

jon12

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Nov 14, 2010
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I get to a point in solving dy/dx= (1)/(squareroot3x+1) where I don't know what to do.
The point I am at is with integral 1(3x+1)^(-1/2) dx
what do i do from there, a little help please.
 
jon12 said:
I get to a point in solving dy/dx= (1)/(squareroot3x+1) where I don't know what to do.
The point I am at is with integral 1(3x+1)^(-1/2) dx
what do i do from there, a little help please.

Substitute:

u = 3x +1

and continue....
 
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