hodasmom said:The problem is x-3y=6, 3x+5y=-10.
I solved 3x+5y=-10
3x-3x+5y=-10-3x
y=-2-(3/5)x <<<<< Now continueCode:5y =-10 - 3x _ _ _ 5 5 5
AND THEN
x-3(-2-3x)=6
x+6+9x=6
10x+6=6
10x+6-6=6-6
10x=0
Somehow I dont think this is right. HELP!!!!
skeeter said:much easier to solve for x in the first equation ...
x = 3y+6
now substitute (3y+6) for x in the second equation ... solve for y, then go back to your sub equation and find x.
btw, your solution for x is correct ... you just took the long road to Hong Kong.
mom, seems you're unaware that if 10x = 0, then x = 0; 10 times 0 = 0 ;hodasmom said:10x=0
Somehow I dont think this is right. HELP!!!!
hodasmom said:The problem is
x - 3y = 6, >>>>> x = 6 + 3y .........................(1)
3x+5y=-10. .......................................(2)
3(6 + 3y) + 5y = -10
18 + 9y + 5y = -10
14y = - 28
y = -2 ........................................(3)
Using (3) in (2)
x = 6 + 3*(-2)
x = 0........................................(4)
check
x - 3y = 0 - 3*(-2) = 6 ................checks
3x + 5y = 3*0 + 5*(-2) = -10.........checks
I solved 3x+5y=-10
3x-3x+5y=-10-3x
5y=-10-3x
_ _
5 5
y=-2-3x
AND THEN
x-3(-2-3x)=6
x+6+9x=6
10x+6=6
10x+6-6=6-6
10x=0
Somehow I dont think this is right. HELP!!!!