This is the problem I'm having great trouble on,,
y=-0.5gt2 + v0tsinΘ + y0
(this is the equation to find the high jumper's trajectory)
y=the height of the jumper(meters)
g=acceleration due to gravity (-9.8 m/s2)
t= time (seconds)
v0= initial velocity of the jumper (m/s)
Θ = launch angle from horizontal (degrees)
y0= initial height (meters) (assuming the jumper starts from the ground, this will be zero.)
question:
If the average running speed of a high jumper is 10m/s and the average launch angle is 42
degrees, find the time the jumper is in the air while clearing a 2m jump. ----------------------------------------------------------------------------------------
I'm having great trouble with this question, so please help me..! I have no idea how to find the time...:-(
y=-0.5gt2 + v0tsinΘ + y0
(this is the equation to find the high jumper's trajectory)
y=the height of the jumper(meters)
g=acceleration due to gravity (-9.8 m/s2)
t= time (seconds)
v0= initial velocity of the jumper (m/s)
Θ = launch angle from horizontal (degrees)
y0= initial height (meters) (assuming the jumper starts from the ground, this will be zero.)
question:
If the average running speed of a high jumper is 10m/s and the average launch angle is 42
degrees, find the time the jumper is in the air while clearing a 2m jump. ----------------------------------------------------------------------------------------
I'm having great trouble with this question, so please help me..! I have no idea how to find the time...:-(