solving absolute-value inequalities: |d + 1| + 8 > 11

This inequality contains an absolute value (how far away a number is from 0)

http://www.purplemath.com/modules/solveabs.htm

So with your equation:

|d+1| +8 > 11
simplify
|d+1| > 3

so (d+1) > 3 or -(d+1) > 3

d+1 > 3 or -d - 1 > 3

Continue to solve for your two solutions. Remember, on the second solution, to divide both sides by -1 at the end so your solution is a negative.
 
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