solving a trigonometric identity

laurendanielle3

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Oct 23, 2008
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i know how to solve most idenities.. but this one on our past test is very tricky.. and no one in my class could figure it out.
here it is...

1-1/2sin2(theta)= sin(cubed)(theta)+soc(cubed)(theta) divided by sin(theta)+cos(theta)
 
laurendanielle3 said:
i know how to solve most idenities.. but this one on our past test is very tricky.. and no one in my class could figure it out.
here it is...

1-1/2sin2(theta)= sin(cubed)(theta)+soc(cubed)(theta) divided by sin(theta)+cos(theta)

Hint:

\(\displaystyle a^3 \, + \, b^3 \, = \, (a \, + \, b)\cdot (a^2 \, - \, a\cdot b \, + \, b^2)\)
 
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