Solving a trig equation?

[TheNascar92]

When i solve the following equation:

2-6sin?=0 (reads 2 minus 6 sin theta equals zero)

i get the answers of 19.47 and 160.53. Could anyone verify this? If i did the work correctly?

By the way the equation is a polar graph that i need to find the zeros for. Just wondering if this makes any sense.

 

[Deleted member 4993]

When i solve the following equation:

2-6sin?=0 (reads 2 minus 6 sin theta equals zero)

i get the answers of 19.47 and 160.53. Could anyone verify this? If i did the work correctly?

By the way the equation is a polar graph that i need to find the zeros for. Just wondering if this makes any sense.

check it with a calculator.

sin(19.47) = ??

and

sin(160.53) = ??

 

[TheNascar92]

they both equal about zero.

But did i go about the correct way to solve it or did i use the wrong process?

I got sin?=1/3 then i did inverse sin of 1/3 to get the 19.47. Since sine is positive in QI and QII i subtracted 180-19.47 to get the second quadrant answer. Is this correct? Im so confused

 

[Deleted member 4993]

Your method is correct - if domain of ? is 0???2?.

In your first reply - you did not explain what you really wanted.