Can I get help with this question? z^6 + (i+1)z^3 + i =0
F frigid New member Joined Nov 22, 2012 Messages 2 Nov 25, 2012 #1 Can I get help with this question? z^6 + (i+1)z^3 + i =0
MarkFL Super Moderator Staff member Joined Nov 24, 2012 Messages 3,021 Nov 25, 2012 #2 I would factor as follows: \(\displaystyle z^6+(1+i)z^3+i=0\) \(\displaystyle (z^6+z^3)+i(z^3+1)=0\) \(\displaystyle z^3(z^3+1)+i(z^3+1)=0\) \(\displaystyle (z^3+i)(z^3+1)=0\) Can you proceed from here?
I would factor as follows: \(\displaystyle z^6+(1+i)z^3+i=0\) \(\displaystyle (z^6+z^3)+i(z^3+1)=0\) \(\displaystyle z^3(z^3+1)+i(z^3+1)=0\) \(\displaystyle (z^3+i)(z^3+1)=0\) Can you proceed from here?
