Solving a Polynomial, Again.

[WonderChidl16]

Okay. One more question, maybe.
Here is the equation:
x⁴-4x²+3=0
I factored this out(Although I'm not sure that was the right route.)
(x²-3)(x²-1)=0
Then....
x²-3=0
x²-1=0
I came out with x equaling:
Plus or Minus square root 3
and Plus or Minus 1

But that isn't what the back of the book said....
Explain, please?

 

[mmm4444bot]

I came out with x equaling:
Plus or Minus square root 3
and Plus or Minus 1

that isn't what the back of the book [says]...

Your work and answers are correct.

x^4 - 4x^2 + 3 = 0

x = ±sqrt(3)

x = ±1

All math texts contain mistakes, so trust but verify! :cool:

 

[Deleted member 4993]

to verify

for x = (±√3) → x^4 - 4x^2 + 3 = (±√3)⁴ - 4*(±√3)² + 3 = 9 -12 +3 = 0 ..........checks

similarly you can verify the other set of answers.