Solving a non-right triangle with 2 angles and 1 side given

[Timcago]

Find the triangle satisfying the given conditions.

a=73.5
Angle B = 61 degrees
Angle C = 83 degrees

180 minus 61 minus 83 gives me a third angle measureo f 36 degrees.

So i have no right angles. Can this be solved using the law of cosines? If so how?

 

[galactus]

Use the law of sines.

\(\displaystyle \frac{a}{sin(A)}=\frac{b}{sin(B)}\)

Solve for b. There's one side down. One to go.

 

[Timcago]

I thought the law of sines only works on right triangles?

oh nvm you are right. I was thinking about the trig ratios

 

[jonboy]

I thought the law of sines only works on right triangles?

oh nvm you are right. I was thinking about the trig ratios

Also Law of Cosines also works on non-right triangles: \(\displaystyle \L \;a^2=b^2+c^2-2(b)(c)CosA\)