Solving a log equation algebraically?

twohaha

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Apr 7, 2012
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18
Find x for

log(base989/942) (((79x)/90) + 1) = x

I can't seem to extract the 1 from the logarithm...
 
Hello, twohaha!

\(\displaystyle \text{Solve for }x\!:\;\;\log_{\frac{989}{942}} \left(\dfrac{79x}{90} + 1\right) \:=\: x\)

It cannot be solved algebraically.

It is a transcendental equation.
It has an \(\displaystyle x\) "inside" a transcendental function (log) and "outside", too.

Other examples are: .\(\displaystyle \begin{Bmatrix} \sin x \:= \: x \\ 3^x \:=\: x \\ \tan^{\text{-}1}x \:= \: x \end{Bmatrix}\)
 
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