Solving (3x + 4)^2 = 6

[npaggs]

I don't know why this is so confusing, but here's what I've done so far.

Foiled 3x + 4 to get

9x^2 + 24x + 16 = 6

Subtract 6 to make equation equal to 0

9x^2 + 24x + 10 = 0

Get 'a' to equal 1

x^2 = 8/3x + 10/3 = 0

Now Do I just plug that into the Quadratic Formula?
Or have I done something wrong / missing something

 

[Loren]

You don't have to get a = 1. You have...

9x^2 + 24x + 10 = 0

a=9, b=24, c=10.

Plug those into the quadratic formula and simplify.

 

[tkhunny]

Foiled 3x + 4 to get

Please forget "FOIL" and just learn to multiply.

9x^2 + 24x + 16 = 6
Now Do I just plug that into the Quadratic Formula?

I'm a little disappointed that you don't seem to know how close you are already to a solution. Taking a step backwards so that you can use a formula probably indicates more fear than confidence.

(3x+4)^2=6 ==> \(\displaystyle 3x+4 = \sqrt{6}\) or \(\displaystyle -(3x+4) = \sqrt{6}\)

Each of those is easily solved for 'x' and they should look awfully familiar.