solving 3 - 3sin(Ø) - 2cos^2(Ø) = 0 for Ø

LaurenK

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Dec 13, 2006
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solving 3 - 3sin(Ø) - 2cos^2(Ø) = 0 for Ø

Can you help me figure out how to do this problem? I don't even know where to start. I'm supposed to solve the following equation for Ø

3 - 3sin(Ø) - 2cos^2(Ø) = 0

Thank you,
Lauren
 
Use \(\displaystyle sin^{2}(\theta)\;+\;cos^{2}(\theta)\;=\;1\) to convert the cosine to sine. Then you have a quadratic in \(\displaystyle sin(\theta)\). You can use the quadratic formula, if all else fails.

\(\displaystyle sin(\theta)\;=\;???\)
 
ok so heres what i did...
2(1-sin^2Ø)+3sinØ-3=0
2sin^2Ø+3sinØ-1=0
a=2 b=3 c=-1
-3 +/- sqrt(3^2-4(2)(-1))/4
i got -3 +/- sqrt(17)/4... is that right?
am i on the right track?
 
pay attention to your signs ...

\(\displaystyle \L -2\sin^2{x} + 3\sin{x} - 1 = 0\)

\(\displaystyle \L 2\sin^2{x} - 3\sin{x} + 1 = 0\)

\(\displaystyle \L (2\sin{x} - 1)(\sin{x} - 1) = 0\)

... and good things happen to make life (and trig equations) much easier.
 
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