Use \(\displaystyle sin^{2}(\theta)\;+\;cos^{2}(\theta)\;=\;1\) to convert the cosine to sine. Then you have a quadratic in \(\displaystyle sin(\theta)\). You can use the quadratic formula, if all else fails.
ok so heres what i did...
2(1-sin^2Ø)+3sinØ-3=0
2sin^2Ø+3sinØ-1=0
a=2 b=3 c=-1
-3 +/- sqrt(3^2-4(2)(-1))/4
i got -3 +/- sqrt(17)/4... is that right?
am i on the right track?
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