Solving 2 simultaneous differential equations

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ddeyv

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Joined
Apr 11, 2020
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11
Hello!
I have been having a hard time learning differential equations, especially in undetermined coefficients.
I do not know how to solve such so if someone please help me with this problem.


QUESTION:

2dx/dt - 3dy/dt + x - y = k
3dx/dt + 2dy/dt - x + cos(t) = 0


I really do not have any ideas where to start on undetermined coefficients and solving simultaneous DE.
Any help will be appreciated! Thank you!
 
ddeyv said:
Hello!
I have been having a hard time learning differential equations, especially in undetermined coefficients.
I do not know how to solve such so if someone please help me with this problem.


QUESTION:

2dx/dt - 3dy/dt + x - y = k
3dx/dt + 2dy/dt - x + cos(t) = 0


I really do not have any ideas where to start on undetermined coefficients and solving simultaneous DE.
Any help will be appreciated! Thank you!
Click to expand...

I forgot to mention.
Please solve for dy/dt.
 
ddeyv said:
Hello!
I have been having a hard time learning differential equations, especially in undetermined coefficients.
I do not know how to solve such so if someone please help me with this problem.


QUESTION:

2dx/dt - 3dy/dt + x - y = k
3dx/dt + 2dy/dt - x + cos(t) = 0


I really do not have any ideas where to start on undetermined coefficients and solving simultaneous DE.
Any help will be appreciated! Thank you!
Click to expand...
To learn the topic, please do a google search with following key-words:

""simultaneous differential equation""

You will find many tutorial videos and solved problems.

Please show us what you have tried and exactly where you are stuck.

Please follow the rules of posting in this forum, as enunciated at:

https://www.freemathhelp.com/forum/threads/read-before-posting.109846/#post-486520

Please share your work/thoughts about this assignment.
 
I tried setting equation 2 into dx/dt then substitute it to equation 1. Thus giving me,

(1/13)(5x - 3y - 3k - 2cos(t)) = dy/dt

But, the answer in the reference I had is,
(1/13)(5x - y - 3k - 2cos(t)) = dy/dt


Is my answer correct and the given answer from the reference is wrong?
 
ddeyv said:
I tried setting equation 2 into dx/dt then substitute it to equation 1. Thus giving me,

(1/13)(5x - 3y - 3k - 2cos(t)) = dy/dt

But, the answer in the reference I had is,
(1/13)(5x - y - 3k - 2cos(t)) = dy/dt


Is my answer correct and the given answer from the reference is wrong?
Click to expand...
Please show your work, step-by-step.
 
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