Solve y=b+(the square root of x + d) for x

[mallorymal]

I really don't know how to do this.

y=b+(the square root of x + d)

We have to figure out what x is.

 

[stapel]

I really don't know how to do this.

y=b+(the square root of x + d)

We have to figure out what x is.

Would you be able to solve for x, if you'd had the following?

. . . . .\(\displaystyle 5\, =\, 2\, +\, \sqrt{x\, +\, 1}\)

Thank you!

Eliz.

 

[mallorymal]

I'm really not sure what you do with the square root thing. Do you just get rid of it?

 

[JohnfromTampa]

Sort of. Isolate the square root, square both sides, and solve for x.

 

[stapel]

I'm really not sure what you do with the square root thing. Do you just get rid of it?

Um... no, you cannot arbitrarily change bits of the equation, at least not if you're wanting to get the right answer! :shock:

From your reply, it sounds as though you aren't very familiar with working with radicals, so you may need more help than we can here provide. (You need to learn about radicals, about solving radical equations, and then about solving literal equations, and that assumes that you're okay with solving linear equations. This material usually takes quite a few days to cover.)

You might want to consider hiring a local qualified tutor, and setting aside a few hours a week (daily is best) for concentrated face-to-face learning. :idea:

Good luck!

Eliz.

 

[Denis]

I'm really not sure what you do with the square root thing. Do you just get rid of it?

[sqrt(n)]^2 = n ; kapish?