solve (x+h) (x+h) -4x squared divided by 2
- Thread starter market
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Since there is no "equals" sign, I'm not sure what equation you're "solving"...? Also, since there are two variables, for which variable are you supposed to solve...? :shock:market said:
Please reply with clarification, including a clear listing of the steps you used to arrive at the answer without understanding any of those steps. Thank you!
Eliz.
kasie-tutor
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Dear market,
Could you please clarify what is being squared? Use the ^ symbol to indicate exponents (powers), and use parentheses to group what is being squared and what is being divided by 2. For example:
[(x + h)(x + h) - 4x^2] / 2
4x^2 means "4 x squared", where only the x is getting squared, then I grouped the whole expression in [ ] brackets because the whole thing is being divided by 2.
Is this the expression you're asking about?
Also, is it an expression (comes with no = sign) or an equation (comes with an = sign)? It matters because in the former case, you simplify (not solve) and in the latter case you simplify and solve.
Another note: You have to FOIL when you multiply binomials, so
\(\displaystyle $(x+h)(x+h)=x^2+xh+xh+h^2=x^2+2xh+h^2$\)
--K
Could you please clarify what is being squared? Use the ^ symbol to indicate exponents (powers), and use parentheses to group what is being squared and what is being divided by 2. For example:
[(x + h)(x + h) - 4x^2] / 2
4x^2 means "4 x squared", where only the x is getting squared, then I grouped the whole expression in [ ] brackets because the whole thing is being divided by 2.
Is this the expression you're asking about?
Also, is it an expression (comes with no = sign) or an equation (comes with an = sign)? It matters because in the former case, you simplify (not solve) and in the latter case you simplify and solve.
Another note: You have to FOIL when you multiply binomials, so
\(\displaystyle $(x+h)(x+h)=x^2+xh+xh+h^2=x^2+2xh+h^2$\)
--K