Solve x = (3y + 2) / (y - 3) for Y (edited)

[Gretta99]

I need help on a Precalculus problem. It has been a long summer and so I've forgotten a few things.

x=(3y+2)/(y-3) Solve for y.
My work
(y-3)x=((3y+2)/(y-3))(y-3)
xy-3x=3y+2
xy=3y+3x+2
y=(3y+3x+2)/(x)

I can't think of any way to isolate y completely on one side without dragging x along with it.

Thanks a ton!

 

[Deleted member 4993]

Re: Solve for Y

I need help on a Precalculus problem. It has been a long summer and so I've forgotten a few things.

x=(3y+2)/(y-3) Solve for y.

I've tried several different ways, but I always end up with y on both sides. I started by multiplying both sides by (y-3) but that left an x attached to half of it.

Thank you so much for your help!

Please show your work - even if you think it is wrong - so that we know where to begin to help you.

 

[Deleted member 4993]

Re: Solve for Y (edited)

I need help on a Precalculus problem. It has been a long summer and so I've forgotten a few things.

x=(3y+2)/(y-3) Solve for y.
My work
(y-3)x=((3y+2)/(y-3))(y-3)
xy-3x=3y+2<<< Now you need to isolate the variable you want solve - in this case 'y'

xy -3y = 2 + 3x

y(x-3) = 2 + 3x

Now finish it...

xy=3y+3x+2
y=(3y+3x+2)/(x)

I can't think of any way to isolate y completely on one side without dragging x along with it.

Thanks a ton!

 

[Gretta99]

Re: Solve for Y (edited)

Thank you! That makes complete sense now!