Solve w = (3y - x)/y for y, c = (-2t + 4)/t for t

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Solve w = (3y - x)/y for y

Solve c = (-2t + 4)/t for t

I've been trying to figure out these problems for a long time now. I would appreciate it if someone could give me step-by-step soultions to both of these problems.
 
Is that \(\displaystyle c=\frac{-2t+4}{t}\) or \(\displaystyle c=-2t+\frac{4}{t}\)?
 
\(\displaystyle \L w = 3y - \frac{x}{y}\)

\(\displaystyle \L wy = 3y^2 - x\)

\(\displaystyle \L 0 = 3y^2 - wy - x\)

\(\displaystyle \L y = \frac{w \pm \sqrt{w^2 + 12x}}{6}\)
 
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