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solve using the principle of zero products
- Thread starter tam67
- Start date
tam67 said:I have two problems that have basiclly the same idea.
The first one is to solve using the principle of zero products
(2x + 2/5)(4x - 1/7)
The second one is, solve by factoring and using the principle of zero products
m^2 - 9/16 = 0
For the first one (2x + 2/5)(4x - 1/7) = 0 , Try this link http://library.thinkquest.org/20991/textonly/alg2/eq.html
Num 2 )
\(\displaystyle m^2 - \frac{9}{16} = 0\)
\(\displaystyle m^2 - \frac{3^2}{4^2}=0\)
\(\displaystyle What \ do \ you \ know \ of \ a^2 - b^2 = factorise \ this ?\)
The zero product property says that if we have two numbers 'a', and 'b' such that 'a * b = 0'; then either a=0, b=0, or both equal 0.tam67 said:I see you factored, the 2nd problem. I understand how to factor but I'm having trouble with the zero principle. I don't understand it. Or better yet, I simply don't even know where to start.
Tammy
Using this, we have 2 problems now to solve
(2x + 2/5)(4x - 1/7) = 0
1st : 2x = - 2/5
x = -2 / 10
x = - 1 / 5
And
4x - 1 / 7 = 0
4x = 1 / 7
x = 1 / 28
The Two Solutions are : ( - 1 / 5 , 1 / 28 )
Hope That Helps !