Solve the equation to determine all possible values of the number

hervorragend

New member
Joined
Oct 4, 2015
Messages
3
attachment.php

Hey guys so here's what I did and I got 0 as one of the numbers. However, on the answer key it also had an 8 as a possible value. I do not know what I did wrong. I need some guidance :)
 

Attachments

  • 20160131_004916.jpg
    20160131_004916.jpg
    225.9 KB · Views: 21
attachment.php

Hey guys so here's what I did and I got 0 as one of the numbers. However, on the answer key it also had an 8 as a possible value. I do not know what I did wrong. I need some guidance :)

You got:

3n = 6\(\displaystyle \sqrt{2n}\)

9n2 = 72n

9n*(n - 8) = 0

Now continue....
 
hervorragend, this first line of yours is wrong for at least three reasons.

\(\displaystyle \sqrt{9 + 5n} \ = \ 3 + \sqrt{2n} \ \ \ ( \ 3 + \sqrt{2n})\)


The expression in parentheses isn't multiplying anything. It's just floating there.

You i) need the expression immediately after the equals sign inside grouping
symbols, and ii) the expression already in parentheses has to be adjacent to it.

The expression on the left-hand side of the equation has to be squared.


(And it would help to have a step where you show squaring each side)
_____________________________________________________

\(\displaystyle \sqrt{9 + 5n} \ = \ 3 + \sqrt{2n} \)

\(\displaystyle (\sqrt{9 + 5n})^2 \ = \ (3 + \sqrt{2n})^2 \)

\(\displaystyle 9 + 5n \ = \ (3 + \sqrt{2n})(3 + \sqrt{2n}) \)

\(\displaystyle 9 + 5n \ = \ 9 + 6\sqrt{2n} + 2n \)


And continue.
 
Top