youknowjojo
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- Feb 26, 2007
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How do i solve:
Tan[(theta/2)+(pi/3)]=1
and
2cos^2(theta) + cos(theta) - 1 = 0
Tan[(theta/2)+(pi/3)]=1
and
2cos^2(theta) + cos(theta) - 1 = 0
solve Tan[(theta/2) + (pi/3)] = 1, 2cos^2(theta) + cos(theta
- Thread starter youknowjojo
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- Apr 12, 2005
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Re: Solving Equations Within Intervals
(theta/2)+(pi/3) = pi/4 + k*pi
Solve for theta.
cos(theta) = (-1 + sqrt(1+4*2))/4
cos(theta) = (-1 - sqrt(1+4*2))/4
You just look at this one. Where is the tangent +1??? pi/4 + k*pi for k an integer. So,...youknowjojo said:
(theta/2)+(pi/3) = pi/4 + k*pi
Solve for theta.
You recognize the Quadratic Structure and just write down the first part.
cos(theta) = (-1 + sqrt(1+4*2))/4
cos(theta) = (-1 - sqrt(1+4*2))/4