Solve rational equation: 3/y + 5 - 1 = 4 - y/2y + 10

[faithdance22]

OK I know the saying, a procrastination on my part does not make an emergency on your part but I would really appreciate a speedy reply if it all possible since this is due tomorrow night and I have exhausted all other options. Here's my problem:

3/y+5 -1 = 4-y/2y+10

And to be specific I literally don't know where to start, so I need help with the whole thing! Sad I know. Thankyou so much in advance for any help!

 

[skeeter]

you need to use proper grouping symbols so that your fractions may be understood

do you mean ...

\(\displaystyle \frac{3}{y+5} - 1 = \frac{4 - y}{2y + 10}\)

or

\(\displaystyle \frac{3}{y+5} - 1 = 4 - \frac{y}{2y + 10}\)

or something else entirely?

 

[faithdance22]

Sorry, the first one.

 

[skeeter]

\(\displaystyle \frac{3}{y+5} - 1 = \frac{4-y}{2y+10}\)

factor the denominator on the right side of the equation ...

\(\displaystyle \frac{3}{y+5} - 1 = \frac{4-y}{2(y+5)}\)

the common denominator is 2(y + 5) ...

\(\displaystyle \frac{6}{2(y+5)} - \frac{2(y+5)}{2(y+5)} = \frac{4-y}{2(y+5)}\)

now, all the denominators are the same ... the numerators form the equation

\(\displaystyle 6 - 2(y + 5) = 4 - y\)

solve the above equation for y ... remember that y cannot equal -5 (do you know why?)

 

[Denis]

Re: Solve rational Equation.

OK I know the saying, a procrastination on my part does not make an emergency on your part but I would really appreciate a speedy reply if it all possible since this is due tomorrow night and I have exhausted all other options. Here's my problem:
3/y+5 -1 = 4-y/2y+10

Next time, use brackets: 3 / (y + 5) - 1 = (4 - y) / (2y + 10)

And what does this mean: "I have exhausted all other options." :?: :shock:

 

[faithdance22]

Thank you guys for all the help and patience.

Exhausting my options of asking a classmate that I'm aqquainted with, a co-worker, reading my textbook, going over lecture notes and other homework options and practically reading everything I could find on the internet on algebra anything really. I was about in tears last night thinking I would never get that problem.

Rest assured, I have this class until August so I'm sure I will return soon! Thanx again <3