Solve r/R = (T/t)^2 Square root of l/L For L

[Dakotadoggy222]

This is my problem r/R=(T/t)^2 Square root of l/L Its asking to solve for L
THis is what i came up with
r/R = (T/t)² V(l/L)
r/R / (T/t)² = V(l/L)
[r/R / (T/t)²]² = l/L
L = l / [r/R / (T/t)²]²

I dont think its right because can you have fractions in the denominator?

 

[wjm11]

Re: Solve For L

This is my problem r/R=(T/t)^2 Square root of l/L Its asking to solve for L
THis is what i came up with
r/R = (T/t)² V(l/L)
r/R / (T/t)² = V(l/L)
[r/R / (T/t)²]² = l/L
L = l / [r/R / (T/t)²]²

I dont think its right because can you have fractions in the denominator?

To simplify further, consider this method to deal with division by a fraction: instead of dividing by the fraction, multiply by its reciprocal. For example,

(a/b)/(c/d) = (a/b)(d/c) = ad/(bc)

 

[Denis]

Re: Solve For L

Changing your "confusing" variables:

a/b = (c/d)^p SQRT(e/f) ; so we're solving for f

square both sides:
a^2 / b^2 = c^(2p) / d^(2p) (e / f)
a^2 / b^2 = c^(2p)e / d^(2p)f
a^2 d^(2p) f = b^2 c^(2p) e

f = b^2 c^(2p) e / [a^2 d^(2p)]