can you help me? :roll: Solve integral: . . .integral (5 / (x^3 + 4x)) dx
S Smily New member Joined May 27, 2006 Messages 22 Jul 29, 2006 #1 can you help me? :roll: Solve integral: . . .integral (5 / (x^3 + 4x)) dx
pka Elite Member Joined Jan 29, 2005 Messages 11,976 Jul 29, 2006 #2 \(\displaystyle \L \frac{5}{{x^3 + 4x}} = \frac{5}{{4x}} + \frac{x}{{x^2 + 4}}\)
S soroban Elite Member Joined Jan 28, 2005 Messages 5,586 Jul 29, 2006 #3 Hello, pka! I think you meant: \(\displaystyle \L\,\frac{5}{x^3\,+\,4x}\:=\:\frac{5}{4}\left[\frac{1}{x}\;-\;\frac{x}{x^2\,+\,4}\right]\)
Hello, pka! I think you meant: \(\displaystyle \L\,\frac{5}{x^3\,+\,4x}\:=\:\frac{5}{4}\left[\frac{1}{x}\;-\;\frac{x}{x^2\,+\,4}\right]\)
pka Elite Member Joined Jan 29, 2005 Messages 11,976 Jul 29, 2006 #4 YES! it is -! Thank you for checking.
