solve inequality with radical

[jazzgirl]

Okay I am not sure on this but here is what I think I am to do.
Here is the problem. I need to solve the inequality.

(2x-9)*square root x+1<0

I need to islolate the radical so

(x+1) < (2x+9)(2x+9)
(x+1)< 4x^2 +36x + 81

Am I on the right track?

 

[Deleted member 4993]

Okay I am not sure on this but here is what I think I am to do.
Here is the problem. I need to solve the inequality.

(2x-9)*square root x+1<0

I need to islolate the radical so

(x+1) < (2x+9)(2x+9)
(x+1)< 4x^2 +36x + 81

Am I on the right track..............No?

I assume you are trying to solve for 'x' - given

\(\displaystyle (2x-9)\cdot \sqrt{x+1} < 0\)

\(\displaystyle \sqrt{(x+1)}\) is always positive. So you need to only deal with the sign of (2x-9). Also you need to make sure x > (-1)