solve inequality andexpress the solution in inteval notation

chabreya said:
1 - x / x^2 <0
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As posted, this means "1 - (x / x<sup>2</sup>) = 1 - (1/x)". Is this what you meant? Or did you mean something like "(1 - x) / x<sup>2</sup>"? Or something else?

When you reply, please show everything you have tried so far. Thank you.

Eliz.
 
Let us assume that the problem is \(\displaystyle \frac{{1 - x}}{{x^2 }} < 0\).
Because \(\displaystyle {x^2 }\) is always non-negative we must consider \(\displaystyle {1 - x}\).
That is negative if \(\displaystyle x > 1\).
 
The question is suppose to be 1-x/X^2-9<0
The answer i got is 1/3<x but i do not think it is right
 
you really need to use grouping symbols in your posts ...

(1 - x)/(x<sup>2</sup> - 9) < 0

critical values are where the expression (1-x)/(x<sup>2</sup> - 9) is equal to zero or is undefined. the critical values of x are x = 1, x = 3, and x = -3

the three critical numbers break up the number line into 4 sections ...

...........-3..............1............3.............
<--------|------------|----------|-------->

check the inequality using any number in each section of the number line ... if that number works (makes the inequality true) then all numbers in that section make the inequality true and that section of the number line is part of the solution set.
 
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