Solve formula A = 1/2h(B + b) for variable b

[jshaziza]

A=1/2h(B+b) solve for b

I know the answer is b=A-1/2hB/ 1/2h

Although I know the answer I need someone to show me the steps of how to get that answer. Thx for any help

 

[Denis]

Repost PROPERLY, with BRACKETS;
like, what does 1/2h mean: 1 divided by (2 times h), or (1/2) times h ?

 

[skeeter]

I know the answer is b=A-1/2hB/ 1/2h

I do not believe your "answer" is correct. It looks as though you wish to solve for one of the base variables in the area formula for a trapezoid ...

\(\displaystyle \L A = \frac{1}{2}h(B+b)\)

multiply both sides by 2 ...

\(\displaystyle \L 2A = h(B + b)\)

divide both sides by h ...

\(\displaystyle \L \frac{2A}{h} = B + b\)

subtract B from both sides ...

\(\displaystyle \L \frac{2A}{h} - B = b\)

... you're done.

 

[jshaziza]

Skeeter you are right about the formula that I want to solve for, I don't know I guess the answer page is wrong. But thanks for showing me how to solve that, it was on the odds section.

 

[Denis]

Skeeter you are right about the formula that I want to solve for, I don't know I guess the answer page is wrong.

Answer page answer: b=A-1/2hB/ 1/2h is correct if shown PROPERLY:
b = (A - (1/2)hB) / ((1/2)h)
b = (A - hB/2) / (h/2)
b = (2A - hB)/2 * (2/h)
b = (2A - hB) / h
b = 2A/h - B : same as Sir Skeeter's