Solve for Y

[msemilygonzalez]

w=2y-x/y

 

[masters]

w=2y-x/y

Hi msemilygonzalez,

This is what you have written. Is it correct?

\(\displaystyle w=2y-\frac{x}{y}\)

Or, is it this way:

\(\displaystyle w=\frac{2y-x}{y}\)

I'm going to assume the first way......

Multiply both sides of your equation by y

\(\displaystyle wy=2y^2-x\)

Next, rearrange to = 0.....

\(\displaystyle 2y^2-wy-x=0\)

Now, use the quadratic formula to solve for y.

Let a = 2, b = -w, c = -x

 

[msemilygonzalez]

I'M SORRY IT'S THE SECOND ONE...

W= 2Y-X
______
Y

 

[masters]

I'M SORRY IT'S THE SECOND ONE...

W= 2Y-X
______
Y

Ok, this one's even easier.

\(\displaystyle w=\frac{2y-x}{y}\)

Multiply both sides by y.

\(\displaystyle wy=2y-x\)

Bring the 2y to the left side.

\(\displaystyle wy-2y=-x\)

Factor out the y on the left side.

\(\displaystyle y(w-2)=-x\)

Finally, divide both sides by (w - 2).

\(\displaystyle y=\frac{-x}{w-2}\)

 

[msemilygonzalez]

Thanks!