Solve for Y

[msemilygonzalez]

w=2y-x/y

 

[masters]

w=2y-x/y

Hi msemilygonzalez,

This is what you have written. Is it correct?

$\displaystyle w=2y-\frac{x}{y}$

Or, is it this way:

$\displaystyle w=\frac{2y-x}{y}$

I'm going to assume the first way......

Multiply both sides of your equation by y

$\displaystyle wy=2y^2-x$

Next, rearrange to = 0.....

$\displaystyle 2y^2-wy-x=0$

Now, use the quadratic formula to solve for y.

Let a = 2, b = -w, c = -x

 

[msemilygonzalez]

I'M SORRY IT'S THE SECOND ONE...

W= 2Y-X
______
Y

 

[masters]

I'M SORRY IT'S THE SECOND ONE...

W= 2Y-X
______
Y

Ok, this one's even easier.

$\displaystyle w=\frac{2y-x}{y}$

Multiply both sides by y.

$\displaystyle wy=2y-x$

Bring the 2y to the left side.

$\displaystyle wy-2y=-x$

Factor out the y on the left side.

$\displaystyle y(w-2)=-x$

Finally, divide both sides by (w - 2).

$\displaystyle y=\frac{-x}{w-2}$

 

[msemilygonzalez]

Thanks!