solve for x: x: -3 (x- 4) <=5 + x

tek

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solve for x

x: -3 ( x- 4) < 5 +x

[7/4,inf) ok this was answer in the book

did they get 7/4 by adding -3 and -4 and did mutiply 4 by x to get. i don't know please help me understnd how they got this answer.
 
Re: solve for x

Why is this posted in the calculus section?. It's basic algebra.
 
Re: solve for x

galactus said:
Why is this posted in the calculus section?. It's basic algebra.
i thought was calcus since was in the Pre- calcus book
 
Re: solve for x

Solve for x in the same way you would a normal equality. Construct your interval based on the end inequality. Example: If x <= c, than the domain is (-infinity .. c]

Note: your book is wrong.

x -3(x-4) <= 5 + x
-3x + 12 <= 5
-3x <= -7
x >= 7/3 NOT 7/4

Construct your interval accordingly.

Remember to flip your inequality when dividing by a negative number:

if a > b
then a - b > 0
then -b > -a
than -a < -b
 
Re: solve for x

To see where you're at; what is:
-3 (x - 4) = ?
 
Re: solve for x

tek said:
i thought was calcus since was in the Pre- calcus book
In English, the prefix "pre" is commonly used to mean "before". A "precalculus" resource covers material that comes before calculus. That's why your book is covering algebra and maybe some trig, but no differential or integral calculus. Calculus will be covered in a calculus book.

Eliz.
 
Re: solve for x

jwpaine said:
Solve for x in the same way you would a normal equality ***. Construct your interval based on the end inequality. Example: If x <= c, than the domain is (-infinity .. c]

Note: your book is wrong.
The problem looks to be: solve -3(x-4) <= 5 + x, in which case the book is correct.

x -3(x-4) <= 5 + x
-3x + 12 <= 5
-3x <= -7
x >= 7/3 NOT 7/4

Construct your interval accordingly.

Remember to flip your inequality when dividing by a negative number: Put this where *** is.

if a > b
then a - b > 0
then -b > -a
than -a < -b
 
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