Solve for x (simple index problem)

[mabentley86]

Hi All,

I can't seem to figure this one out, I have a feeling I should use a logarithm. Any suggestions much appreciated.

\(\displaystyle 2(2^{2x})-5(2^x)+2=0\)

 

[pka]

use a logarithm. Any suggestions much appreciated.
\(\displaystyle 2(2^{2x})-5(2^x)+2=0\)

Can you solve \(\displaystyle 2u^2-5u+2=0~?\)
If so, there are two values for \(\displaystyle u\).
Set each of those \(\displaystyle =2^x\), and solve for \(\displaystyle x\).