solve for x y=(x-9)/(3x-1) (3x-1)y=x-9 3xy-y=x-9 3xy-x=y-9 x(3y-1)=y-9 x=(y-9)/(3y-1) that's the answer i get... the book answer says x=(y+9)/(1-3y) is my math wrong or is that the same answer just written different?