solve for f'(x)=0

[Guest]

solve for f'(x)=0
f(x) = [ln(3x^2-6x)]^4
you use chain rule? 4[[ln(3x^2-6x)]^3][how do you find the derivative on the inside, I forget!]

ahhh,
thanks for all the help today

 

[royhaas]

\(\displaystyle \{ln\[g(x)]\}' = g'(x)/g(x)\).