Solve for b

[walleyh]

I am not sure where to go with this problem. I have to solve for b

ab+cd = cb-b

First thing I did was ab+b = cb-cd

Would it be 2b = cb-cd/a
then b = c-cd/a

I am sure there is division there but I am totally confused from this point on. Can anyone help.

Thanks.

 

[Artimid]

Well, while I am not one of the math experts here, I think I can possible help a bit.
What I actually did when I solved this was subtracted AB from both sides so I got cd=cb-b-ab.
Then I factored the b, thus leaving b(c-1-a)=cd
Then, all that was left was to divide with b=(cb)/(c-1-a)

I used quotes because it makes it easier on me, but they aren't actually there.

So, to show it like how these guys sometimes do.

ab+cd = cb-b
Subtract ab from both sides.
cd=cb-b-ab
Factor the B cd=b*(c-1-a)
Divide (c-1-a) from both sides

b = cd/(c-1-a)

 

[walleyh]

Thank you that really helps. Right after I posted I realized I need to get all the terms with B on the same side.
Your explanation helped to realize what I needed to do.