Solve equations by graphing method/Divide by long division;

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gijas

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Solve equations by graphing method/Divide using long division;

Solves the system of equations by graphing method:

6x-y=-5
4x-2y=6

6x-y=-5 = y=-6x-5
4x-2y=6 = ?

let y=0 solve for x

4x-2(0)=6
4x=6
x=3/2?

I understand slope and intercept but my problem is getting these into y intercept form to enter into my graphing calculator to find the intersection.





Another problem that I need some help with is a long division equation;

Divide: (2x^3 + 3x - 4))/((x + 2)

Here is what I have so far:

(x + 2))/((2x^3 + 3x - 4)

=2x^2 - 4x

I need to get to - 2x^2 - 4x - 11 - 26/x + 2

How do I do that.
 
Last edited:
gijas said:
6x-y=-5

4x-2y=6

6x-y=-5 = y=-6x-5
-5 = y ?
Please type each equation on its own line, from now on. :cool:

​

my problem is getting these into [slope-intercept] form
Click to expand...

6x - y = -5

(1) Add y to both sides

(2) Add 5 to both sides


4x - 2y = 6

(1) Divide both sides by 2

(2) Add y to both sides

(3) Subtract 3 from both sides



Divide: (2x^3 + 3x - 4))/((x + 2)

I need to get to - 2x^2 - 4x - 11 - 26/x + 2

How do I do that.
Click to expand...

There are two sign errors, in that answer. Both terms 2x^2 and 11 should be positive.

Use longhand polynomial division. Have you learned about it?
 
mmm4444bot said:
6x - y = -5

(1) Add y to both sides

(2) Add 5 to both sides

y = 6x + 5

4x - 2y = 6

(1) Divide both sides by 2

(2) Add y to both sides

(3) Subtract 3 from both sides

y = 2x - 3




There are two sign errors, in that answer. Both terms 2x^2 and 11 should be positive.

Use longhand polynomial division. Have you learned about it?
Click to expand...



Yes I have. I just dont get how to arrive at the answer..

2x^2 - 4x + 11 - 26/x + 2

..where I can get the first half the answer 2x^2 - 4 x
but after that I DONT SEE HOW TO ARRIVE AT + 11 and THE REMAINDER OF 26?
 
Last edited:
gijas said:

Yes I have. I just dont get how to arrive at the answer..

2x^2 - 4x + 11 - 26/(x + 2)

where I can get the first half the answer 2x^2 - 4 x

but after that I DONT SEE HOW TO ARRIVE AT + 11 and THE REMAINDER OF 26?
Click to expand...

The remainder is -26.

Also, please note the grouping symbols that I added above in blue. They are very important, when typing algebraic ratios.

If you leave them off, then your typing means this, instead:

\(\displaystyle 2x^2 - 4x + 11 - \frac{26}{x} + 2\)



Well, if you understand enough about polynomial long division to get the first two terms of the quotient, what happened after that? Without seeing your work, I'm not sure why you stopped.

capture.JPG
 
mmm4444bot said:
The remainder is -26.

Also, please note the grouping symbols that I added above in blue. They are very important, when typing algebraic ratios.

If you leave them off, then your typing means this, instead:

\(\displaystyle 2x^2 - 4x + 11 - \frac{26}{x} + 2\)



Well, if you understand enough about polynomial long division to get the first two terms of the quotient, what happened after that? Without seeing your work, I'm not sure why you stopped.

View attachment 1510
Click to expand...


I understand what you guys are getting to. I saw right away my mistake when you wrote out the long division problem. I subtracted 3x from 4x^2 instead of bringing it down to the next step. My mistake is in proper grouping.. I see this now. Thank you. It really helps me when things are explained this way. Im a visual learner.
 
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