I am having trouble solving for g'(t), since I have forgotten how to solve an equation with negative exponents. Can somebody show me the steps? thanks again!!
Solve for g'(t) given that g(t) = -2
∆y + y = (x + ∆x)-2
∆y = (x + ∆x)-2 - t-2
Ok 2 steps in and I am lost. I know that negative exponent is the reciprocal, but am still confused on how to simplify and solve. thanks!!
Solve for g'(t) given that g(t) = -2
∆y + y = (x + ∆x)-2
∆y = (x + ∆x)-2 - t-2
Ok 2 steps in and I am lost. I know that negative exponent is the reciprocal, but am still confused on how to simplify and solve. thanks!!