solve each system

stuckonmath

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Joined
Sep 9, 2013
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Solve each system

x+y+2z=11
x+y+3z=14
x+2y-z=5
solution or no solution or infinite solution state

How do I solve this. Book does state how but I do not understand.
please help. thank you! :D
 
Solve each system

x+y+2z=11
x+y+3z=14
x+2y-z=5
solution or no solution or infinite solution state

How do I solve this. Book does state how but I do not understand.
please help. thank you! :D
x+y+2z=11
x+y+3z=14

Implies
z=3 do you see why?
 
Solve each system

x+y+2z=11
x+y+3z=14
x+2y-z=5
solution or no solution or infinite solution state

As you can see the matrix of coefficients has a nice inverse.
So there is a unique solution.
Multiply that inverse by \(\displaystyle \left[ {\begin{array}{*{20}{c}}{11}\\
{14}\\
5
\end{array}} \right]\)
 
Solve each system

x+y+2z=11
x+y+3z=14
x+2y-z=5
solution or no solution or infinite solution state

How do I solve this. Book does state how but I do not understand.
What method is the book wanting you to use? We can try to find online lessons that teach the necessary topics, but we'll need some direction from you. Thank you! ;)
 
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