Solve 0.45 = (a - x(bcd + bce + bf)) / (a + x(bcg - bcd -bce -bf)) for x

[vindiou]

Hi everyone,

0.45 = (a - x(bcd + bce + bf)) / (a + x(bcg - bcd -bce -bf))
x = ?

I'm stuck and I need help! (I'm a 56 yo guy and school classes are very far...)

Thanks!

 

[tkhunny]

Hi everyone,

0.45 = (a - x(bcd + bce + bf)) / (a + x(bcg - bcd -bce -bf))
x = ?

I'm stuck and I need help! (I'm a 56 yo guy and school classes are very far...)

Thanks!

The appearance seems a bit pointless. Can you solve \(\displaystyle 0.45 = \dfrac{a - xH}{a+x(J-H)}\), for x?

 

[vindiou]

The appearance seems a bit pointless. Can you solve \(\displaystyle 0.45 = \dfrac{a - xH}{a+x(J-H)}\), for x?

Thanks, I solved it, x = 0.55a / (0.45bcg + 0.55b(cd + ce + f)), merry xmas

 

[JeffM]

The appearance seems a bit pointless. Can you solve \(\displaystyle 0.45 = \dfrac{a - xH}{a+x(J-H)}\), for x?

Ahh, I do not think it pointless at all. Finding the relatively simple in the seemingly complex is one of the skills that math teaches you.

 

[Denis]

Well, Sir Vindiou he no seem too interested...edited his post to a point!!

 

[JeffM]

Well, Sir Vindiou he no seem too interested...edited his post to a point!!

Which obviously entails that it cannot be pointless.

 

[Denis]

0.45 = (a - x(bcd + bce + bf)) / (a + x(bcg - bcd -bce -bf))
x = ?

Since you're solving for x, then the rest is assumed to be givens; so simplify:
u = bcd + bce + bf
v = (bcg - bcd -bce -bf

Equation becomes:
(a - xu) / (a + xv) = 9/20

Let us know if yer still alive Sir V !!