solutions of carbohydrates

[jkarling]

If you wanted to make a 15% carbohydrate solution, and deliver 60grams of carbohydrate, then you need to mix the 60 grams of carbohydrates in ? milliliters of water ????

 

[Unknown008]

1 mL has a mass of 1 g

So, you have 15% of carbohydrate, the rest being water (100% - 15% = 85%)

60 g -> 15%
1% -> ? g
85% -> ? g

Then, convert that mass of water into mL of water.

 

[soroban]

Hello, jkarling!

VERY clumsy wording . . .

How many milliliters of water must be added to 60 ml of carbohydrate
to make a 15% solution?

Let \(\displaystyle x\) = number of ml of water.

The final solution contains \(\displaystyle x+60\) ml.

We want \(\displaystyle \dfrac{x}{x+60}\) to equal 15%.

Our equation is: .\(\displaystyle \dfrac{x}{x+60} \:=\:0.15\)

 

[Unknown008]

Unless the carbohydrate was indeed a solid...

 

[Unknown008]

1 mL has a mass of 1 g

So, you have 15% of carbohydrate, the rest being water (100% - 15% = 85%)

60 g -> 15%
1% -> ? g
85% -> ? g

Then, convert that mass of water into mL of water.

1 mL has a mass of 1 g → That is true for water at NTP

mL is a volume. To convert it to mass (g) we need to multiply with density (which is different for different materal).

This is water and since the pressure/temperature is not specified, I took rtp.

And the density of water is 1 kg/L... and with such limited information, the mass of the carbohydrate cannot be obtained, so a more accurate method is impossible.

 

[Deleted member 4993]

This is water and since the pressure/temperature is not specified, I took rtp.

And the density of water is 1 kg/L... and with such limited information, the mass of the carbohydrate cannot be obtained, so a more accurate method is impossible.

I realized that - you had meant that statement to be for water only.

That is why I deleted my post - but you caught hold of it before I deleted that post.

 

[Unknown008]

Oh, oops, sorry xD