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Solution please!
- Thread starter Allanr13
- Start date
Have you read the post: "Read Before Posting!!"The base of a solid is the region in the first quadrant enclosed by the graph of y=2-x^(2) and the coordinate axes. If every cross section of the solid perpendicular to the y-axis is a square, the volume of the solid is given by...
You should get the idea that we dont "give answers," rather we check your work and give hints.
The first thing you have to do is finish the "..." at the end of the question: what general procedure would you use to find volume?
HallsofIvy
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- Jan 27, 2012
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No, this is not an area rotated around an axis and so has nothing to do with "disks and washers". What can do is use the fact that the volume of a solid is given by an area times a length perpendicular to the area. With "rotation" such an area is a "disk or washer". Here the area is that of a square. What is the length of a side of each such square and what is its area?
While it is true that the volume of a cube is s^3, the shape of this object is far from cubic.The base of a solid is the region in the first quadrant enclosed by the graph of y=2-x^(2) and the coordinate axes. If every cross section of the solid perpendicular to the y-axis is a square, the volume of the solid is given by...
1) Draw a picture of the base shape in the x-y plane
2) "cross section perpendicular to the y-axis" is square means that the z-boundary is equal to the x-boundary of the solid.
3) find the cross section area as a function of y
4) What is an increment of volume, dV ? What can you integrate to find the Volume?
HallsofIvy
Elite Member
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- Jan 27, 2012
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- 7,763
If something has an "area" then it is two-dimensiona and does not HAVE a "volume".well its area would be given by s^(2) while volume would be s^(3)