Solid Geometry Question

[Vivi]

A right circular cone and a sphere have equal volumes. If the radius of the base of the cone is 2x and the radius of the sphere is 3x, what is the height of the cone in terms of x?

Possible answers are...
A. X
B. 3x over 2
C. 4x over 3
D. 20x
E. 27x

Can anyone help?

This is what I've figured

Volume of cone = 1/3pr(2nd power) h= 1/3p(2x)(2nd power) h= 4/3px(2 power) h

 

[galactus]

\(\displaystyle \L\\\frac{1}{3}{\pi}(2x)^{2}h=\frac{4}{3}{\pi}(3x)^{3}\)

Solve for h. What makes you doubt your answer?. I believe you're onto something.