So close but I'm missing something important!

gusterguy

New member
Joined
Nov 23, 2007
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6
"If g=y(4-y), what is -2g in terms of y?

So I assume this is a variation of a function problem yes?

I plug the -2 in so the equation reads g = -2y(4-y). I finish the equation so it reads -8y + 2y(squared). I take the y back out so the equation reads g = y(2y-8). However that isn't an answer choice...can anyone help me identify where I went wrong so I can better recognize what to do in the future? I feel like I know how to do this type of problem but I'm missing something key here and I really want to learn how to better handle these problems...

Answer choices are: 2y(4 + y), 2y(y - 4), y(8-2y), -y(2y-8), and -2y(y-4).

Thanks guys!

Jeff
 
Gusterguy,

You're doing fine -- just working too hard. You've already gotten the answer. It's the second one: 2y(y - 4). You had g = -2y(4-y); just distribute the "-" inside the parentheses.
 
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