slope form through given point and is perpendicular

[jb]

Stuck again Please show me how to find the answers.

Write the slope-intercept form of an equation that passes through given point and is perpendicular to the graph of each equation.
( -2, 0 ), y = x=-6

also if you please

Write an equation of the line with y-tintercept -6 that is parrallel to the graph of
x - 3y = 8

 

[tkhunny]

Stuck again Please show me how to find the answers.

Write the slope-intercept form of an equation that passes through given point and is perpendicular to the graph of each equation.
( -2, 0 ), y = x=-6

also if you please

Write an equation of the line with y-tintercept -6 that is parrallel to the graph of
x - 3y = 8

These are simple definition problems. You may have missed something in class or in your book. This is all you need:

Slope-Intercept Form: y = mx+b
Point-Slope Form: (y-k) = m(x-h)
Lines are parallel when their slopes are the same.
Lines are perpendicular when their slopes multiply to -1.

x - 3y = 8
Put it in Slope Intercept Form
-3y = -x + 8
y = (1/3)x - (8/3) ==> Slope is 1/3

This doesn't make any sense: "( -2, 0 ), y = x=-6"

 

[jb]

Sorry it's supposed to be
( -2, 0 ), y = x - 6

 

[tkhunny]

Now show me that you know SOMETHING. Find the slope and intercept of that line you have repaired.