Sketch a graph of a function ...

K_Swiss

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Sketch a graph of a function f(x) that is differentiable and that satisfies the following conditions.

\(\displaystyle f'(x) > 0\), when \(\displaystyle x < -5\)
\(\displaystyle f'(x) < 0\), when \(\displaystyle -5 < x < 1\) and when \(\displaystyle x > 1\)
\(\displaystyle f'(-5) = 0\) and \(\displaystyle f'(1) = 0\)
\(\displaystyle f(-5) = 6\) and \(\displaystyle f(1) = 2\)

Did I do this question correctly, if not, please fix my mistake!

Legend:
\(\displaystyle f'(x)\) is pink
\(\displaystyle f(x)\) is red
 

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K_Swiss,

Your red graph, f(x), has a positive slope between –2 and 1, indicating that f’(x) would be positive in this region. That would conflict with the requirement that

f’(x) < 0, when –5 < x < 1.

Your red graph needs to maintain a negative slope throughout the specified region, flatten to horizontal at x = 1, then turn negative again for x > 1.
 
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