Orpington3
New member
- Joined
- Feb 23, 2010
- Messages
- 2
An object weighing 16 lb is dropped from rest on the surface of a calm lake and thereafter starts to sink. While its weight tends to force it downward, the buoyancy of the object tends to force it back upward. If this buoyancy force is one of 6 lb and the resistance of the water (in pounds) is numerically equal to twice the square of the velocity (in feet per second), find the formula for the velocity of the sinking object as a function of time.
I honestly don't even know how to start this problem, but I do know that the answer is
v=(((5)^(1/2))(1-e^(-8t((5)^(1/2)))/(1+e^(-8t((5)^(1/2))
which might be easier to understand as:
v equals radical 5 ( 1 - e to the -8 radical 5 times t ) all divided by one plus e to the -8 radical 5 times t
all help will be greatly appreciated!
I honestly don't even know how to start this problem, but I do know that the answer is
v=(((5)^(1/2))(1-e^(-8t((5)^(1/2)))/(1+e^(-8t((5)^(1/2))
which might be easier to understand as:
v equals radical 5 ( 1 - e to the -8 radical 5 times t ) all divided by one plus e to the -8 radical 5 times t
all help will be greatly appreciated!